(x^2-4x+4)(3x-5)=0

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Solution for (x^2-4x+4)(3x-5)=0 equation: 


Simplifying
(x2 + -4x + 4)(3x + -5) = 0

Reorder the terms:
(4 + -4x + x2)(3x + -5) = 0

Reorder the terms:
(4 + -4x + x2)(-5 + 3x) = 0

Multiply (4 + -4x + x2) * (-5 + 3x)
(4(-5 + 3x) + -4x * (-5 + 3x) + x2(-5 + 3x)) = 0
((-5 * 4 + 3x * 4) + -4x * (-5 + 3x) + x2(-5 + 3x)) = 0
((-20 + 12x) + -4x * (-5 + 3x) + x2(-5 + 3x)) = 0
(-20 + 12x + (-5 * -4x + 3x * -4x) + x2(-5 + 3x)) = 0
(-20 + 12x + (20x + -12x2) + x2(-5 + 3x)) = 0
(-20 + 12x + 20x + -12x2 + (-5 * x2 + 3x * x2)) = 0
(-20 + 12x + 20x + -12x2 + (-5x2 + 3x3)) = 0

Combine like terms: 12x + 20x = 32x
(-20 + 32x + -12x2 + -5x2 + 3x3) = 0

Combine like terms: -12x2 + -5x2 = -17x2
(-20 + 32x + -17x2 + 3x3) = 0

Solving
-20 + 32x + -17x2 + 3x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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